What is 2y^2+2x^2=1 ?

The solution to 2y^2+2x^2=1 is Circle with (a,b)=(0,0),r=sqrt(1/2)

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2y^2+2x^2=1

2 y^{2} + 2 x^{2} = 1

(a, b) = (0, 0), r = \frac{1}{2}

Solution steps

2 y^{2} + 2 x^{2} = 1

Rewrite

2 y^{2} + 2 x^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{1}{2}

(x + 2)^{2} + y^{2} = 10

x^{2} + z^{2} = 5

x^{2} + z^{2} = 2

(x - 2)^{2} + (y - 3)^{2} = 6^{2}

\frac{( x + 2 ) ^{2}}{9} + (\frac{y}{3})^{2} = 1

What is 2y^2+2x^2=1 ?
The solution to 2y^2+2x^2=1 is Circle with (a,b)=(0,0),r=sqrt(1/2)