What is 2y+x=(x-1)^2+y^2-5 ?

The solution to 2y+x=(x-1)^2+y^2-5 is Circle with (a,b)=(3/2 ,1),r=(sqrt(29))/2

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2y+x=(x-1)^2+y^2-5

2 y + x = (x - 1)^{2} + y^{2} - 5

(a, b) = (\frac{3}{2}, 1), r = \frac{29}{2}

Solution steps

2 y + x = (x - 1)^{2} + y^{2} - 5

Rewrite

2 y + x = (x - 1)^{2} + y^{2} - 5

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 1)^{2} = (\frac{29}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 1), r = \frac{29}{2}

x^{(2)} + y^{(2)} - 2 x - 4 y + 3 = 0

45 x^{2} + 45 y^{2} = - 4 x

x^{2} - 2 x + y^{2} = \frac{466}{25}

(x + 1)^{2} + (y - 3)^{2} = (50)^{2}

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

What is 2y+x=(x-1)^2+y^2-5 ?
The solution to 2y+x=(x-1)^2+y^2-5 is Circle with (a,b)=(3/2 ,1),r=(sqrt(29))/2