What is x^2+y^2-12x-12y+36=0 ?

The solution to x^2+y^2-12x-12y+36=0 is Circle with (a,b)=(6,6),r=6

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x^2+y^2-12x-12y+36=0

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

(a, b) = (6, 6), r = 6

Solution steps

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

Rewrite

x^{2} + y^{2} - 12 x - 12 y + 36 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 6)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (6, 6), r = 6

(x + 3)^{2} + (y - 2)^{2} = 36

4 x^{2} + 4 y^{2} - 64 = 0

x^{2} + 2 x \cdot 3 + 3^{2} + y^{2} - 2 y \cdot \frac{2}{3} + (\frac{2}{3})^{2} = 4^{2}

x^{2} - 8 x + 16 + y^{2} - 18 y + 81 = 48

(x + 3)^{2} + (y - 2)^{2} = 49

What is x^2+y^2-12x-12y+36=0 ?
The solution to x^2+y^2-12x-12y+36=0 is Circle with (a,b)=(6,6),r=6