What is (x-1)^2+y^2-1= 3/6 x ?

The solution to (x-1)^2+y^2-1= 3/6 x is Circle with (a,b)=(5/4 ,0),r= 5/4

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(x-1)^2+y^2-1= 3/6 x

(x - 1)^{2} + y^{2} - 1 = \frac{3}{6} x

(a, b) = (\frac{5}{4}, 0), r = \frac{5}{4}

Solution steps

(x - 1)^{2} + y^{2} - 1 = \frac{3}{6} x

Rewrite

(x - 1)^{2} + y^{2} - 1 = \frac{3}{6} x

in the form of the standard circle equation

(x - \frac{5}{4})^{2} + (y - 0)^{2} = (\frac{5}{4})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{4}, 0), r = \frac{5}{4}

(x - 6)^{2} + (y - 10)^{2} = 5

2 x^{2} + 2 y^{2} + 8 x - 8 y = 34

x^{2} + y^{2} - 4 - 2 x - 4 y = 0

(x - 2)^{2} + (y + 3)^{2} = 4^{2}

x^{2} + y^{2} - 6 y = 7

What is (x-1)^2+y^2-1= 3/6 x ?
The solution to (x-1)^2+y^2-1= 3/6 x is Circle with (a,b)=(5/4 ,0),r= 5/4