What is (x-1)^2+(y+3)^2=3 ?

The solution to (x-1)^2+(y+3)^2=3 is Circle with (a,b)=(1,-3),r=sqrt(3)

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(x-1)^2+(y+3)^2=3

(x - 1)^{2} + (y + 3)^{2} = 3

(a, b) = (1, - 3), r = 3

Solution steps

(x - 1)^{2} + (y + 3)^{2} = 3

Rewrite

(x - 1)^{2} + (y + 3)^{2} = 3

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 3

x^{2} + y^{2} - 5 x + 4 y = 16

x^{2} + 2 x + 1 + y^{2} + 4 y + 4 - 36 = 0

(x - 3)^{2} + (y - 4)^{2} - 9 = y - x + 1

(x - 1)^{2} + (y + 11)^{2} = 100

9 x^{(2)} + 9 y^{(2)} - 6 x + 24 y = 19

What is (x-1)^2+(y+3)^2=3 ?
The solution to (x-1)^2+(y+3)^2=3 is Circle with (a,b)=(1,-3),r=sqrt(3)