What is x^2+y^2+10x-23=0 ?

The solution to x^2+y^2+10x-23=0 is Circle with (a,b)=(-5,0),r=4sqrt(3)

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x^2+y^2+10x-23=0

x^{2} + y^{2} + 10 x - 23 = 0

(a, b) = (- 5, 0), r = 43

Solution steps

x^{2} + y^{2} + 10 x - 23 = 0

Rewrite

x^{2} + y^{2} + 10 x - 23 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 0)^{2} = (43)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 0), r = 43

(X - 4)^{2} + (Y + 9)^{2} = 2

(x - 4)^{2} + (y - 4)^{2} = 3^{2}

x^{(2)} + y^{(2)} - 6 x + 2 y - 6 = 0

2 x^{2} + 2 y^{2} + 14 x - 10 y + 35 = 0

x^{2} + y^{2} + x + 6 y - 55 = 0

What is x^2+y^2+10x-23=0 ?
The solution to x^2+y^2+10x-23=0 is Circle with (a,b)=(-5,0),r=4sqrt(3)