What is x^2+y^2+14x-10y+65=0x ?

The solution to x^2+y^2+14x-10y+65=0x is Circle with (a,b)=(-7,5),r=3

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x^2+y^2+14x-10y+65=0x

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 x

(a, b) = (- 7, 5), r = 3

Solution steps

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 \cdot x

Rewrite

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 x

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 7, 5), r = 3

3 x^{2} + 3 y^{2} - 30 x - 6 y + 75 = 0

0.2 x^{2} + x + 0.2 y^{2} - 4 y = 1

x^{2} + y^{2} - 5 x = 20 - 2 y

(x^{2} + 14 x 9) + (y^{2} + 12 y + 36) = 36 + 49 + 36

x^{2} + y^{2} - 10 x + 7 y + 30 = 0

What is x^2+y^2+14x-10y+65=0x ?
The solution to x^2+y^2+14x-10y+65=0x is Circle with (a,b)=(-7,5),r=3