What is x^2-6y+y^2+5=0 ?

The solution to x^2-6y+y^2+5=0 is Circle with (a,b)=(0,3),r=2

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x^2-6y+y^2+5=0

x^{2} - 6 y + y^{2} + 5 = 0

(a, b) = (0, 3), r = 2

Solution steps

x^{2} - 6 y + y^{2} + 5 = 0

Rewrite

x^{2} - 6 y + y^{2} + 5 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 3), r = 2

x^{2} + y^{2} + \frac{2}{3} x - \frac{1}{2} y - \frac{13}{48} = 0

x^{2} + y^{2} - 2 x - 20 y + 100 = 0

2 x^{2} + 8 x + 2 y^{2} - 8 y - 4 = 0

x^{2} + y^{2} - 8 x - 12 y + 27 = 0

4 = (6 - x)^{2} + (2 - y)^{2}

What is x^2-6y+y^2+5=0 ?
The solution to x^2-6y+y^2+5=0 is Circle with (a,b)=(0,3),r=2