What is 21sqrt(5)=a^2+b^2 ?

The solution to 21sqrt(5)=a^2+b^2 is Circle with (a,b)=(0,0),r=sqrt(21)\sqrt[4]{5}

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21sqrt(5)=a^2+b^2

215 = a^{2} + b^{2}

Solution steps

215 = a^{2} + b^{2}

Rewrite

215 = a^{2} + b^{2}

in the form of the standard circle equation

Therefore the circle properties are:

(x)^{2} + (y - 4)^{2} = 73

x^{2} + y^{2} - x - y - \frac{1}{2} = 0

(x - 5)^{2} + (y + 4)^{2} = 100

x^{2} + y^{2} \leq \frac{3}{4}

x^{2} - 8 x + 16 + y^{2} + 2 y + 1 = 4

What is 21sqrt(5)=a^2+b^2 ?
The solution to 21sqrt(5)=a^2+b^2 is Circle with (a,b)=(0,0),r=sqrt(21)\sqrt[4]{5}