What is 32=(x-1)^2+(y+0.5)^2 ?

The solution to 32=(x-1)^2+(y+0.5)^2 is Circle with (a,b)=(1,-1/2),r=4sqrt(2)

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32=(x-1)^2+(y+0.5)^2

32 = (x - 1)^{2} + (y + 0.5)^{2}

(a, b) = (1, - \frac{1}{2}), r = 42

Solution steps

32 = (x - 1)^{2} + (y + 0.5)^{2}

Rewrite

32 = (x - 1)^{2} + (y + 0.5)^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{1}{2}), r = 42

\frac{x ^{2} + y ^{2} - 2 x + y - 3}{2} > 0

x^{2} + y^{2} = 53

(x + \frac{π}{2})^{2} + ((y - \frac{1}{2})^{2} = 2^{2})

(x + 3)^{2} + (y - 2)^{2} = \frac{25}{4}

x^{2} + y^{2} = 13

What is 32=(x-1)^2+(y+0.5)^2 ?
The solution to 32=(x-1)^2+(y+0.5)^2 is Circle with (a,b)=(1,-1/2),r=4sqrt(2)