What is (x^2+2x+1)+(y^2-6y+9)=-7+1+9 ?

The solution to (x^2+2x+1)+(y^2-6y+9)=-7+1+9 is Circle with (a,b)=(-1,3),r=sqrt(3)

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(x^2+2x+1)+(y^2-6y+9)=-7+1+9

(x^{2} + 2 x + 1) + (y^{2} - 6 y + 9) = - 7 + 1 + 9

(a, b) = (- 1, 3), r = 3

Solution steps

x^{2} + 2 x + 1 + (y^{2} - 6 y + 9) = - 7 + 1 + 9

Rewrite

x^{2} + 2 x + 1 + (y^{2} - 6 y + 9) = - 7 + 1 + 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 3

4 x^{(2)} + 40 x + 4 y^{(2)} - 32 y = 5

x^{2} + y^{2} - 10 x + 2 y + 20 = 0

(X + 8)^{2} + (Y + 6)^{2} = 100

(x^{2} + y^{2} - 1)^{2} > 9

9 x^{2} - 6 x + 9 + 9 y^{2} + 24 y + 144 = 19 + 9 + 144

What is (x^2+2x+1)+(y^2-6y+9)=-7+1+9 ?
The solution to (x^2+2x+1)+(y^2-6y+9)=-7+1+9 is Circle with (a,b)=(-1,3),r=sqrt(3)