What is (x-(-1))^2+(y-3)^2=(sqrt(3))^2 ?

The solution to (x-(-1))^2+(y-3)^2=(sqrt(3))^2 is Circle with (a,b)=(-1,3),r=sqrt((\sqrt{3))^2}

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(x-(-1))^2+(y-3)^2=(sqrt(3))^2

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

(a, b) = (- 1, 3), r = (3)^{2}

Solution steps

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

Rewrite

(x - (- 1))^{2} + (y - 3)^{2} = 3^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = ((3)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = (3)^{2}

(x - 6)^{2} + (y + 5)^{2} = 4^{2}

x^{2} + y^{2} - 2 x + 6 y - 90 = 0

4 (x + 3)^{2} + 4 (y - 0)^{2} = 16

3 x^{2} + 3 y^{2} = 48

x^{2} + y^{2} + 2 x - 6 y - 40 = 0

What is (x-(-1))^2+(y-3)^2=(sqrt(3))^2 ?
The solution to (x-(-1))^2+(y-3)^2=(sqrt(3))^2 is Circle with (a,b)=(-1,3),r=sqrt((\sqrt{3))^2}