What is x^2+y^2=47+3x ?

The solution to x^2+y^2=47+3x is Circle with (a,b)=(3/2 ,0),r=(sqrt(197))/2

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x^2+y^2=47+3x

x^{2} + y^{2} = 47 + 3 x

(a, b) = (\frac{3}{2}, 0), r = \frac{197}{2}

Solution steps

x^{2} + y^{2} = 47 + 3 x

Rewrite

x^{2} + y^{2} = 47 + 3 x

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 0)^{2} = (\frac{197}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 0), r = \frac{197}{2}

x^{2} + y^{2} - 6 y = 55

(x + y)^{(2)} = x 2 + 2 x y + y 2

x^{2} + y^{2} = 25 (0, - 5)

x^{2} = - y^{2} + 9

x^{2} = - y^{2} + 8

What is x^2+y^2=47+3x ?
The solution to x^2+y^2=47+3x is Circle with (a,b)=(3/2 ,0),r=(sqrt(197))/2