What is x^2+(y-9)^2=8 ?

The solution to x^2+(y-9)^2=8 is Circle with (a,b)=(0,9),r=sqrt(8)

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x^2+(y-9)^2=8

x^{2} + (y - 9)^{2} = 8

(a, b) = (0, 9), r = 8

Solution steps

x^{2} + (y - 9)^{2} = 8

Rewrite

x^{2} + (y - 9)^{2} = 8

in the form of the standard circle equation

(x - 0)^{2} + (y - 9)^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (0, 9), r = 8

2 x^{2} + 2 y^{2} + 28 y - 8 y + 4 = 0

x^{2} + (y - 9)^{2} = 1

x^{2} + y^{2} + 5 x + 4 y - 34 = 0

(x + 7)^{2} + y^{2} = 36

(x + 6)^{2} + (y - 4)^{2} = 73

What is x^2+(y-9)^2=8 ?
The solution to x^2+(y-9)^2=8 is Circle with (a,b)=(0,9),r=sqrt(8)