What is (x+5)^2+(y-2)^2=sqrt(2) ?

The solution to (x+5)^2+(y-2)^2=sqrt(2) is Circle with (a,b)=(-5,2),r=sqrt(\sqrt{2)}

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(x+5)^2+(y-2)^2=sqrt(2)

(x + 5)^{2} + (y - 2)^{2} = 2

(a, b) = (- 5, 2), r = 2

Solution steps

(x + 5)^{2} + (y - 2)^{2} = 2

Rewrite

(x + 5)^{2} + (y - 2)^{2} = 2

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 2

x^{2} + y^{2} + 10 x - 10 y + 25 = 0

(x - 2)^{2} + (y - 5)^{2} = 13

(x)^{2} + (y)^{2} = 169

x^{2} + y^{2} + 10 x + 16 y - 107 = 0

(x - 5)^{2} + (y - 3)^{2} = 16

What is (x+5)^2+(y-2)^2=sqrt(2) ?
The solution to (x+5)^2+(y-2)^2=sqrt(2) is Circle with (a,b)=(-5,2),r=sqrt(\sqrt{2)}