What is (x+4)^2+(y+1)^2=9 ?

The solution to (x+4)^2+(y+1)^2=9 is Circle with (a,b)=(-4,-1),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+4)^2+(y+1)^2=9

(x + 4)^{2} + (y + 1)^{2} = 9

(a, b) = (- 4, - 1), r = 3

Solution steps

(x + 4)^{2} + (y + 1)^{2} = 9

Rewrite

(x + 4)^{2} + (y + 1)^{2} = 9

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 1), r = 3

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

3 x^{2} + 3 y^{2} - 3 x - 3 y - 9 = 0

(x - 6)^{2} + (y + 2)^{2} = 16

x^{2} - 8 x + 16 + y^{2} - 4 y + 4 = (34)^{2}

(x - 3)^{2} + (y - 4)^{2} = (2)^{2}

What is (x+4)^2+(y+1)^2=9 ?
The solution to (x+4)^2+(y+1)^2=9 is Circle with (a,b)=(-4,-1),r=3