What is y^2-2sqrt(6)x+2sqrt(5)y+5=-x^2 ?

The solution to y^2-2sqrt(6)x+2sqrt(5)y+5=-x^2 is Circle with (a,b)=(sqrt(6),-sqrt(5)),r=sqrt(6)

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y^2-2sqrt(6)x+2sqrt(5)y+5=-x^2

y^{2} - 26 x + 25 y + 5 = - x^{2}

(a, b) = (6, - 5), r = 6

Solution steps

y^{2} - 26 x + 25 y + 5 = - x^{2}

Rewrite

y^{2} - 26 x + 25 y + 5 = - x^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 5))^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (6, - 5), r = 6

(x - 5)^{2} + (y - 22)^{2} = 10

y^{2} = - x^{2} + 1

y^{2} = - x^{2} + 5

(x - 2)^{2} + y^{2} = 49

(x + 5)^{2} + (y + 1)^{2} = 9

What is y^2-2sqrt(6)x+2sqrt(5)y+5=-x^2 ?
The solution to y^2-2sqrt(6)x+2sqrt(5)y+5=-x^2 is Circle with (a,b)=(sqrt(6),-sqrt(5)),r=sqrt(6)