What is 61=x^2+4x+y^2-8y ?

The solution to 61=x^2+4x+y^2-8y is Circle with (a,b)=(-2,4),r=9

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61=x^2+4x+y^2-8y

61 = x^{2} + 4 x + y^{2} - 8 y

(a, b) = (- 2, 4), r = 9

Solution steps

61 = x^{2} + 4 x + y^{2} - 8 y

Rewrite

61 = x^{2} + 4 x + y^{2} - 8 y

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 4)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 2, 4), r = 9

5 x^{2} + 5 y^{2} = 100

x^{2} - x + y^{2} - \frac{1}{2} y - \frac{75}{16} = 0

x^{2} + y^{2} - 6 y - 198 = 0

(x - 2)^{2} + (y - 25)^{2} = 1 5^{2}

(x - 0)^{2} + (y - 1)^{2} = 4

What is 61=x^2+4x+y^2-8y ?
The solution to 61=x^2+4x+y^2-8y is Circle with (a,b)=(-2,4),r=9