What is (x-(-5))^2+(y-7)^2=(sqrt(11))^2 ?

The solution to (x-(-5))^2+(y-7)^2=(sqrt(11))^2 is Circle with (a,b)=(-5,7),r=sqrt((\sqrt{11))^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-(-5))^2+(y-7)^2=(sqrt(11))^2

(x - (- 5))^{2} + (y - 7)^{2} = (11)^{2}

(a, b) = (- 5, 7), r = (11)^{2}

Solution steps

(x - (- 5))^{2} + (y - 7)^{2} = (11)^{2}

Rewrite

(x - (- 5))^{2} + (y - 7)^{2} = 11^{2}

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 7)^{2} = ((11)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 5, 7), r = (11)^{2}

x^{2} + y^{2} + 10 x - 8 y + 36 = 0

(x - 1)^{2} + (y + 11)^{2} + (0 - 8)^{2} = 100

x^{2} + y^{2} + 5 x - 2 y - 8 = 0

122 = a^{2} + b^{2}

x^{2} + y^{2} - 6 x + 14 y + 42 = 0

What is (x-(-5))^2+(y-7)^2=(sqrt(11))^2 ?
The solution to (x-(-5))^2+(y-7)^2=(sqrt(11))^2 is Circle with (a,b)=(-5,7),r=sqrt((\sqrt{11))^2}