What is (x-15/4)^2+y^2=64 ?

The solution to (x-15/4)^2+y^2=64 is Circle with (a,b)=(15/4 ,0),r=8

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(x-15/4)^2+y^2=64

(x - \frac{15}{4})^{2} + y^{2} = 64

(a, b) = (\frac{15}{4}, 0), r = 8

Solution steps

(x - \frac{15}{4})^{2} + y^{2} = 64

Rewrite

(x - \frac{15}{4})^{2} + y^{2} = 64

in the form of the standard circle equation

(x - \frac{15}{4})^{2} + (y - 0)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (\frac{15}{4}, 0), r = 8

2 x^{2} + 2 y^{2} + 4 x + 16 y + 1 = 0

(x + 89)^{2} + (y + 85)^{2} = (25)^{2}

x^{2} + y^{2} = 4 y + 4

(x - 5)^{2} + (y - 4)^{2} = 1

x^{2} + 2 x + y^{2} + 4 y - 11 = 0

What is (x-15/4)^2+y^2=64 ?
The solution to (x-15/4)^2+y^2=64 is Circle with (a,b)=(15/4 ,0),r=8