What is (x^2)/1+(y^2)/1 =1 ?

The solution to (x^2)/1+(y^2)/1 =1 is Circle with (a,b)=(0,0),r=1

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(x^2)/1+(y^2)/1 =1

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

(a, b) = (0, 0), r = 1

Solution steps

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

Rewrite

\frac{x ^{2}}{1} + \frac{y ^{2}}{1} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

(x + 2)^{2} + (y + 2)^{2} = 4

(x + 6)^{2} + (y - 10)^{2} = 12

(x - (- 2))^{2} + (y - (- 1))^{2} = (3)^{2}

x^{2} + y^{2} - 9 x + 4 y - 138 = 0

x^{2} + y^{2} - 6 x + 2 y = 0

What is (x^2)/1+(y^2)/1 =1 ?
The solution to (x^2)/1+(y^2)/1 =1 is Circle with (a,b)=(0,0),r=1