What is 3x^2+3y^2-6x+9y+2=0 ?

The solution to 3x^2+3y^2-6x+9y+2=0 is Circle with (a,b)=(1,-3/2),r=(sqrt(31))/(2sqrt(3))

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3x^2+3y^2-6x+9y+2=0

3 x^{2} + 3 y^{2} - 6 x + 9 y + 2 = 0

(a, b) = (1, - \frac{3}{2}), r = \frac{31}{2 3}

Solution steps

3 x^{2} + 3 y^{2} - 6 x + 9 y + 2 = 0

Rewrite

3 x^{2} + 3 y^{2} - 6 x + 9 y + 2 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{3}{2}))^{2} = (\frac{31}{2 3})^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{3}{2}), r = \frac{31}{2 3}

x^{2} + y^{2} - 3 x - 7 y + 12 = 0

(x + 6)^{2} + (y - 7)^{2} = 9

x^{2} + y^{2} - 6 x + 4 y - 23 = 0

x^{2} + y^{2} - 4 x + 10 y + 22 = 0

(x - 1)^{2} + (y + 2)^{2} = 25

What is 3x^2+3y^2-6x+9y+2=0 ?
The solution to 3x^2+3y^2-6x+9y+2=0 is Circle with (a,b)=(1,-3/2),r=(sqrt(31))/(2sqrt(3))