What is 18x^2+18y^2-36=0 ?

The solution to 18x^2+18y^2-36=0 is Circle with (a,b)=(0,0),r=sqrt(2)

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18x^2+18y^2-36=0

18 x^{2} + 18 y^{2} - 36 = 0

(a, b) = (0, 0), r = 2

Solution steps

18 x^{2} + 18 y^{2} - 36 = 0

Rewrite

18 x^{2} + 18 y^{2} - 36 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

34 (x - 9)^{2} + 34 (y + 8)^{2} = 3 x - 5 y + 1

x^{2} + y^{2} - 8 x - 4 y + 11 = 0

(x + 9)^{2} + (y - 1)^{2} = 36

4 x^{2} + 4 y^{2} - 4 x + 24 y = - 1

x^{2} + y^{2} - x - 6 y - 5 = 0

What is 18x^2+18y^2-36=0 ?
The solution to 18x^2+18y^2-36=0 is Circle with (a,b)=(0,0),r=sqrt(2)