What is the tangent of y=sqrt(4x+84),(4,10) ?

The tangent of y=sqrt(4x+84),(4,10) is y= 1/5 x+46/5

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tangent of y=sqrt(4x+84),(4,10)

tangent of

y = 4 x + 84, (4, 10)

y = \frac{1}{5} x + \frac{46}{5}

Solution steps

Find the slope of

y = 4 x + 84 : \frac{d y}{d x} = \frac{1}{x + 21}

Compute the slope of

y = 4 x + 84

(4, 10) : m = \frac{1}{5}

Find the line with slope m=

\frac{1}{5}

and passing through

(4, 10) : y = \frac{1}{5} x + \frac{46}{5}

y = \frac{1}{5} x + \frac{46}{5}

\frac{d}{d x} (3 x^{2} (2 x + 5)^{3})

\int \frac{cos ( \frac{π}{x ^{9}} )}{x ^{10}} d x

\int_{1}^{2} t t - 1 d t

x \to c lim (\frac{27}{18})

e^{6 x}

What is the tangent of y=sqrt(4x+84),(4,10) ?
The tangent of y=sqrt(4x+84),(4,10) is y= 1/5 x+46/5