What is the integral from 1 to 2 of (x^2) ?

The integral from 1 to 2 of (x^2) is 7/3

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integral from 1 to 2 of (x^2)

\int_{1}^{2} (x^{2}) d x

\frac{7}{3}

Decimal Notation

2.33333 \dots

Solution steps

\int_{1}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{2}

= [\frac{x ^{3}}{3}]_{1}^{2}

Compute the boundaries:

\frac{7}{3}

= \frac{7}{3}

\int 9 x^{- 3} d x

\frac{d}{d x} (\frac{2 x}{7 x ^{2} + 1})

y^{^{''}} + 256 y = sec (16 x)

y = 12 (x - \frac{1}{x})^{2}, at x = 2

What is the integral from 1 to 2 of (x^2) ?
The integral from 1 to 2 of (x^2) is 7/3