What is the derivative of (t^3)/3 ?

The derivative of (t^3)/3 is t^2

What is the first derivative of (t^3)/3 ?

The first derivative of (t^3)/3 is t^2

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derivative of

\frac{t ^{3}}{3}

t^{2}

Solution steps

\frac{d}{d t} (\frac{t ^{3}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d t} (t^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} \cdot 3 t^{3 - 1}

Simplify

\frac{1}{3} \cdot 3 t^{3 - 1} : t^{2}

= t^{2}

f (x) = \frac{1}{x ^{4}}, (- 3, \frac{1}{81})

\frac{1}{1 - x}, 12

\int \frac{2 x ^{3}}{x ^{2} - 4} d x

\frac{d}{d x} (∣ x - 3 ∣ - ∣ 2 x - 2 ∣ - 1 x e [- 2, 2])

\frac{d}{d x} (1 + x ln (x y - 5))

What is the derivative of (t^3)/3 ?
The derivative of (t^3)/3 is t^2
What is the first derivative of (t^3)/3 ?
The first derivative of (t^3)/3 is t^2