What is the answer to log_{2}(2x+3)=3 ?

The answer to log_{2}(2x+3)=3 is x= 5/2

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log_{2}(2x+3)=3

lo g_{2} (2 x + 3) = 3

x = \frac{5}{2}

Decimal

x = 2.5

Solution steps

lo g_{2} (2 x + 3) = 3

Apply log rules

2 x + 3 = 8

Solve

2 x + 3 = 8 : x = \frac{5}{2}

x = \frac{5}{2}

lo g_{10} (x) + lo g_{10} (x + 4) = 3

lo g_{4} (5 x + 6) = 0

lo g_{9} (x) + lo g_{9} (8 x - 1) = 1

lo g_{2} (7 x - 5) = - 2

lo g_{10} (3 x + 9) = \frac{1}{3}