What is the answer to log_{4}(2x-1)=1 ?

The answer to log_{4}(2x-1)=1 is x= 5/2

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log_{4}(2x-1)=1

lo g_{4} (2 x - 1) = 1

x = \frac{5}{2}

Decimal

x = 2.5

Solution steps

lo g_{4} (2 x - 1) = 1

Apply log rules

2 x - 1 = 4

Solve

2 x - 1 = 4 : x = \frac{5}{2}

x = \frac{5}{2}

lo g_{3} (7 x - 5) = 2

lo g_{10} (x) = lo g_{10} (3) + 1

lo g_{\frac{1}{5}} (2 x - 3) = - 2

lo g_{10} (2 x + 8) = 2

lo g_{10} (8 x) - lo g_{10} (2) = lo g_{10} (32)