What is the answer to 2\times log_{10}(x)-log_{10}(x)=1 ?

The answer to 2\times log_{10}(x)-log_{10}(x)=1 is x=10

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2\times log_{10}(x)-log_{10}(x)=1

2 \cdot lo g_{10} (x) - lo g_{10} (x) = 1

x = 10

Solution steps

2 lo g_{10} (x) - lo g_{10} (x) = 1

Add similar elements:

2 lo g_{10} (x) - lo g_{10} (x) = lo g_{10} (x)

lo g_{10} (x) = 1

Apply log rules

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

lo g_{2} (- 3 x + 8) = 7

lo g_{64} (x) = - \frac{3}{2}

lo g_{2} (x + 2) = - 1

lo g_{3} (x^{2} - 5 x - 9) = 3

lo g_{5} (4 x + 5) = 2

What is the answer to 2\times log_{10}(x)-log_{10}(x)=1 ?
The answer to 2\times log_{10}(x)-log_{10}(x)=1 is x=10
Solve for x: 2\times log_{10}(x)-log_{10}(x)=1
The solution is x=10