What is the answer to solvefor y,x=y^{2/3} ?

The answer to solvefor y,x=y^{2/3} is y=xsqrt(x) {x>= 0},y=-xsqrt(x) {x>= 0}

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solvefor y,x=y^{2/3}

solve for

y, x = y^{\frac{2}{3}}

y = x x {x \geq 0}, y = - x x {x \geq 0}

Solution steps

x = y^{\frac{2}{3}}

Take both sides of the equation to the power of

3 : x^{3} = y^{2}

x^{3} = y^{2}

Solve

x^{3} = y^{2} : y = x x, y = - x x

y = x x, y = - x x

Verify Solutions:

y = x x {x \geq 0}, y = - x x {x \geq 0}

The solutions are

y = x x {x \geq 0}, y = - x x {x \geq 0}

y, x = 3 \frac{- 8 y ^{3}}{y ^{3} - 1}

x + 78 = x + 6

8 3 10 x - 15 = 17

3 2 x - 4 = - 2

6 = x - 2

What is the answer to solvefor y,x=y^{2/3} ?
The answer to solvefor y,x=y^{2/3} is y=xsqrt(x) {x>= 0},y=-xsqrt(x) {x>= 0}