What is the answer to solvefor a,c=sqrt(a^2+b^2) ?

The answer to solvefor a,c=sqrt(a^2+b^2) is a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)

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solvefor a,c=sqrt(a^2+b^2)

solve for

a, c = a^{2} + b^{2}

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

Solution steps

c = a^{2} + b^{2}

Square both sides:

c^{2} = a^{2} + b^{2}

c^{2} = a^{2} + b^{2}

Solve

c^{2} = a^{2} + b^{2} : a = c^{2} - b^{2}, a = - c^{2} - b^{2}

a = c^{2} - b^{2}, a = - c^{2} - b^{2}

2 3 x + 7 = 19

x^{2} - 4 = x + 4

2 x - 1 + 5 = 2

3 x - 2 - 4 = - 1

x + 4 = 2 x - 1

What is the answer to solvefor a,c=sqrt(a^2+b^2) ?
The answer to solvefor a,c=sqrt(a^2+b^2) is a=sqrt(c^2-b^2),a=-sqrt(c^2-b^2)