What is the answer to sqrt(2^2+x^2)=4 ?

The answer to sqrt(2^2+x^2)=4 is x=2sqrt(3),x=-2sqrt(3)

Solve for x: sqrt(2^2+x^2)=4

The solution is x=2sqrt(3),x=-2sqrt(3)

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Popular >

2^{2} + x^{2} = 4

x = 23, x = - 23

Decimal

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

2^{2} + x^{2} = 4

Square both sides:

4 + x^{2} = 16

4 + x^{2} = 16

Solve

4 + x^{2} = 16 : x = 23, x = - 23

x = 23, x = - 23

Verify Solutions:

x = 23

True

, x = - 23

True

The solutions are

x = 23, x = - 23

6 + 22 - 3 x = x

(3 x + 5)^{\frac{2}{3}} + 4 = 29

x + 4 + 2 x - 9 = 4

- 12 = - 6 x + 4

5 x - 3 - 2 x - 1 = 3 x - 2

What is the answer to sqrt(2^2+x^2)=4 ?
The answer to sqrt(2^2+x^2)=4 is x=2sqrt(3),x=-2sqrt(3)
Solve for x: sqrt(2^2+x^2)=4
The solution is x=2sqrt(3),x=-2sqrt(3)