What is the answer to 1/(3x^{2/3)}=1 ?

The answer to 1/(3x^{2/3)}=1 is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))

Solve for x: 1/(3x^{2/3)}=1

The solution is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))

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\frac{1}{3 x ^{\frac{2}{3}}} = 1

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

Decimal

x = 0.19245 \dots, x = - 0.19245 \dots

Solution steps

\frac{1}{3 x ^{\frac{2}{3}}} = 1

Multiply both sides by

3 x^{\frac{2}{3}}

\frac{1}{3 x ^{\frac{2}{3}}} \cdot 3 x^{\frac{2}{3}} = 1 \cdot 3 x^{\frac{2}{3}}

Simplify

1 = 3 x^{\frac{2}{3}}

Switch sides

3 x^{\frac{2}{3}} = 1

Divide both sides by

3

x^{\frac{2}{3}} = \frac{1}{3}

Take both sides of the equation to the power of

3 : x^{2} = \frac{1}{27}

x^{2} = \frac{1}{27}

Solve

x^{2} = \frac{1}{27} : x = \frac{1}{3 3}, x = - \frac{1}{3 3}

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

Verify Solutions:

x = \frac{1}{3 3}

True

, x = - \frac{1}{3 3}

True

The solutions are

x = \frac{1}{3 3}, x = - \frac{1}{3 3}

y, y - 2 x^{2} - 2 x + 2 + 1 = 0

x + 5 + 3 x + 4 = 7

x = 12

10 = \frac{1}{2 x 1 - x ^{2}}

0.137 = Y^{\frac{1}{3}} \cdot 0.28

What is the answer to 1/(3x^{2/3)}=1 ?
The answer to 1/(3x^{2/3)}=1 is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))
Solve for x: 1/(3x^{2/3)}=1
The solution is x= 1/(3sqrt(3)),x=-1/(3sqrt(3))