What is the answer to (-2x^2+25)/(sqrt(25-x^2))=0 ?

The answer to (-2x^2+25)/(sqrt(25-x^2))=0 is x= 5/(sqrt(2)),x=-5/(sqrt(2))

Solve for x: (-2x^2+25)/(sqrt(25-x^2))=0

The solution is x= 5/(sqrt(2)),x=-5/(sqrt(2))

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\frac{- 2 x ^{2} + 25}{25 - x ^{2}} = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal

x = 3.53553 \dots, x = - 3.53553 \dots

Solution steps

\frac{- 2 x ^{2} + 25}{25 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 25 = 0

Solve

- 2 x^{2} + 25 = 0 : x = \frac{5}{2}, x = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

Verify Solutions:

x = \frac{5}{2}

True

, x = - \frac{5}{2}

True

The solutions are

x = \frac{5}{2}, x = - \frac{5}{2}

7 x - 54 - x = - 6

5 x - 1 = 3 x + 19

2 x - 7 = x + 6

3 x - 7 + 5 = 20

8 x - 23 - 4 = 1

What is the answer to (-2x^2+25)/(sqrt(25-x^2))=0 ?
The answer to (-2x^2+25)/(sqrt(25-x^2))=0 is x= 5/(sqrt(2)),x=-5/(sqrt(2))
Solve for x: (-2x^2+25)/(sqrt(25-x^2))=0
The solution is x= 5/(sqrt(2)),x=-5/(sqrt(2))