What are the solutions to the equation x^3-14x-x^2+24=0 ?

The solutions to the equation x^3-14x-x^2+24=0 are x=2,x=3,x=-4

Find the zeros of x^3-14x-x^2+24=0

The zeros of x^3-14x-x^2+24=0 are x=2,x=3,x=-4

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x^{3} - 14 x - x^{2} + 24 = 0

x = 2, x = 3, x = - 4

Solution steps

x^{3} - 14 x - x^{2} + 24 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} - x^{2} - 14 x + 24 = 0

Factor

x^{3} - x^{2} - 14 x + 24 : (x - 2) (x - 3) (x + 4)

(x - 2) (x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 3 = 0 or x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 2, x = 3, x = - 4

2 x^{4} - 15 x^{3} + 32 x^{2} - 30 x + 56 = 0

g, g (3216) = x^{3} - 29

x^{3} - 4 x^{2} - 11 x - 6 = 0

x^{3} - 3 x + 5

y, 4 y - 4 x^{3} = 0

What are the solutions to the equation x^3-14x-x^2+24=0 ?
The solutions to the equation x^3-14x-x^2+24=0 are x=2,x=3,x=-4
Find the zeros of x^3-14x-x^2+24=0
The zeros of x^3-14x-x^2+24=0 are x=2,x=3,x=-4