What are the solutions to the equation x^4+2x^3+4x^2-2x-5=0 ?

The solutions to the equation x^4+2x^3+4x^2-2x-5=0 are x=-1,x=1,x=-1+2i,x=-1-2i

Find the zeros of x^4+2x^3+4x^2-2x-5=0

The zeros of x^4+2x^3+4x^2-2x-5=0 are x=-1,x=1,x=-1+2i,x=-1-2i

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x^{4} + 2 x^{3} + 4 x^{2} - 2 x - 5 = 0

x = - 1, x = 1, x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{4} + 2 x^{3} + 4 x^{2} - 2 x - 5 = 0

Factor

x^{4} + 2 x^{3} + 4 x^{2} - 2 x - 5 : (x + 1) (x - 1) (x^{2} + 2 x + 5)

(x + 1) (x - 1) (x^{2} + 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x^{2} + 2 x + 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x^{2} + 2 x + 5 = 0 : x = - 1 + 2 i, x = - 1 - 2 i

The solutions are

x = - 1, x = 1, x = - 1 + 2 i, x = - 1 - 2 i

m^{3} + 3 m^{2} - 4 = 0

- x^{3} + x^{2} + 10 x + 8 = 0

x^{3} - 3 x^{2} + 3 x + 7 = 0

- x^{3} + 6 x^{2} - 11 x + 6

3 x^{3} - 17 x^{2} + 18 x + 8 = 0

What are the solutions to the equation x^4+2x^3+4x^2-2x-5=0 ?
The solutions to the equation x^4+2x^3+4x^2-2x-5=0 are x=-1,x=1,x=-1+2i,x=-1-2i
Find the zeros of x^4+2x^3+4x^2-2x-5=0
The zeros of x^4+2x^3+4x^2-2x-5=0 are x=-1,x=1,x=-1+2i,x=-1-2i