What are the solutions to the equation roots x^3+2x^2-3x-6 ?

The solutions to the equation roots x^3+2x^2-3x-6 are x=-2,x=-sqrt(3),x=sqrt(3)

Find the zeros of roots x^3+2x^2-3x-6

The zeros of roots x^3+2x^2-3x-6 are x=-2,x=-sqrt(3),x=sqrt(3)

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roots

x^{3} + 2 x^{2} - 3 x - 6

x = - 2, x = - 3, x = 3

Solution steps

x^{3} + 2 x^{2} - 3 x - 6

The roots are the intercepts with the x-axis

(y = 0)

x^{3} + 2 x^{2} - 3 x - 6 = 0

Factor

x^{3} + 2 x^{2} - 3 x - 6 : (x + 2) (x + 3) (x - 3)

(x + 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 2, x = - 3, x = 3

y, 8 y^{3} - 1 = 0

y^{3} - 27 = 0

x^{3} + 5 x^{2} + 4 x + 20 = 0

- 2 x^{8} + 3 x^{6} + x^{4} - 57 x^{2} - 40 = 0

2 x^{3} - 6 x^{2} - 10 x + 30 = 0

What are the solutions to the equation roots x^3+2x^2-3x-6 ?
The solutions to the equation roots x^3+2x^2-3x-6 are x=-2,x=-sqrt(3),x=sqrt(3)
Find the zeros of roots x^3+2x^2-3x-6
The zeros of roots x^3+2x^2-3x-6 are x=-2,x=-sqrt(3),x=sqrt(3)