What are the solutions to the equation -x^3+2x^2+6x+8=0 ?

The solutions to the equation -x^3+2x^2+6x+8=0 are x=4,x=-1+i,x=-1-i

Find the zeros of -x^3+2x^2+6x+8=0

The zeros of -x^3+2x^2+6x+8=0 are x=4,x=-1+i,x=-1-i

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- x^{3} + 2 x^{2} + 6 x + 8 = 0

x = 4, x = - 1 + i, x = - 1 - i

Solution steps

- x^{3} + 2 x^{2} + 6 x + 8 = 0

Factor

- x^{3} + 2 x^{2} + 6 x + 8 : - (x - 4) (x^{2} + 2 x + 2)

- (x - 4) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x^{2} + 2 x + 2 = 0

Solve

x - 4 = 0 : x = 4

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = 4, x = - 1 + i, x = - 1 - i

x^{4} + 4 x^{3} = 0

5 x^{3} + 27 x^{2} - 11 x + 5

x^{5} - x^{4} - x^{3} + x^{2} - 2 x + 2 = 0

3 x^{4} + 4 x^{3} + 6 x - 4 = 0

n^{3} - 9 n^{2} - n + 9 = 0

What are the solutions to the equation -x^3+2x^2+6x+8=0 ?
The solutions to the equation -x^3+2x^2+6x+8=0 are x=4,x=-1+i,x=-1-i
Find the zeros of -x^3+2x^2+6x+8=0
The zeros of -x^3+2x^2+6x+8=0 are x=4,x=-1+i,x=-1-i