What are the solutions to the equation 0=(x^2+1)^2 ?

The solutions to the equation 0=(x^2+1)^2 are x=i,x=-i

Find the zeros of 0=(x^2+1)^2

The zeros of 0=(x^2+1)^2 are x=i,x=-i

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0 = (x^{2} + 1)^{2}

x = i, x = - i

Solution steps

0 = (x^{2} + 1)^{2}

Switch sides

(x^{2} + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

The solutions are

x = i, x = - i

x^{6} - 1

x^{6} + 1

5 x^{3} - 4 x^{2} + \frac{4}{5} x = 0

x^{3} + 3 x^{2} + 12 x + 4 = 0

x^{5} + x^{4} + x^{3} + x^{2} + x + 1

What are the solutions to the equation 0=(x^2+1)^2 ?
The solutions to the equation 0=(x^2+1)^2 are x=i,x=-i
Find the zeros of 0=(x^2+1)^2
The zeros of 0=(x^2+1)^2 are x=i,x=-i