What are the solutions to the equation roots 2x^3-5x^2+x+2 ?

The solutions to the equation roots 2x^3-5x^2+x+2 are x=1,x=-1/2 ,x=2

Find the zeros of roots 2x^3-5x^2+x+2

The zeros of roots 2x^3-5x^2+x+2 are x=1,x=-1/2 ,x=2

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roots

2 x^{3} - 5 x^{2} + x + 2

x = 1, x = - \frac{1}{2}, x = 2

Solution steps

2 x^{3} - 5 x^{2} + x + 2

The roots are the intercepts with the x-axis

(y = 0)

2 x^{3} - 5 x^{2} + x + 2 = 0

Factor

2 x^{3} - 5 x^{2} + x + 2 : (x - 1) (2 x + 1) (x - 2)

(x - 1) (2 x + 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x - 2 = 0 : x = 2

The solutions are

x = 1, x = - \frac{1}{2}, x = 2

y^{4} - 4 = 0

z^{6} + 6 z^{3} + 10 = 0

- 2 x^{4} + x^{3} - x^{2} + 4 x

- 3 x^{3} + 5 x^{2} - 27 x + 45 = 0

2 x^{4} - 9 x^{3} + 17 x^{2} - 36 x + 36 = 0

What are the solutions to the equation roots 2x^3-5x^2+x+2 ?
The solutions to the equation roots 2x^3-5x^2+x+2 are x=1,x=-1/2 ,x=2
Find the zeros of roots 2x^3-5x^2+x+2
The zeros of roots 2x^3-5x^2+x+2 are x=1,x=-1/2 ,x=2