What are the solutions to the equation -3z^3+140-139z+38z^2=0 ?

The solutions to the equation -3z^3+140-139z+38z^2=0 are z=4,z= 5/3 ,z=7

Find the zeros of -3z^3+140-139z+38z^2=0

The zeros of -3z^3+140-139z+38z^2=0 are z=4,z= 5/3 ,z=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 z^{3} + 140 - 139 z + 38 z^{2} = 0

z = 4, z = \frac{5}{3}, z = 7

Decimal

z = 4, z = 1.66666 \dots, z = 7

Solution steps

- 3 z^{3} + 140 - 139 z + 38 z^{2} = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- 3 z^{3} + 38 z^{2} - 139 z + 140 = 0

Factor

- 3 z^{3} + 38 z^{2} - 139 z + 140 : - (z - 4) (3 z - 5) (z - 7)

- (z - 4) (3 z - 5) (z - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

z - 4 = 0 or 3 z - 5 = 0 or z - 7 = 0

Solve

z - 4 = 0 : z = 4

Solve

3 z - 5 = 0 : z = \frac{5}{3}

Solve

z - 7 = 0 : z = 7

The solutions are

z = 4, z = \frac{5}{3}, z = 7

x^{3} - 4 x^{2} - x + 4

2 x^{3} + x - 5 = 0

2 x^{3} + 6 x - 1 = 0

x^{4} - 4 x^{3} - x + 2 = 0

w^{4} + 36 = 13 w^{2}

What are the solutions to the equation -3z^3+140-139z+38z^2=0 ?
The solutions to the equation -3z^3+140-139z+38z^2=0 are z=4,z= 5/3 ,z=7
Find the zeros of -3z^3+140-139z+38z^2=0
The zeros of -3z^3+140-139z+38z^2=0 are z=4,z= 5/3 ,z=7