What are the solutions to the equation 4x^3-6x^2+2x=0 ?

The solutions to the equation 4x^3-6x^2+2x=0 are x=0,x= 1/2 ,x=1

Find the zeros of 4x^3-6x^2+2x=0

The zeros of 4x^3-6x^2+2x=0 are x=0,x= 1/2 ,x=1

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4 x^{3} - 6 x^{2} + 2 x = 0

x = 0, x = \frac{1}{2}, x = 1

Decimal

x = 0, x = 0.5, x = 1

Solution steps

4 x^{3} - 6 x^{2} + 2 x = 0

Factor

4 x^{3} - 6 x^{2} + 2 x : 2 x (2 x - 1) (x - 1)

2 x (2 x - 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 1 = 0 or x - 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = \frac{1}{2}, x = 1

y^{4} - 6 y^{2} = - 5

x^{3} + 5 x^{2} = 4 x + 20

x^{4} + 62 x^{2} + 128 x + 65

a^{4} + a^{3} + a^{2} + a + 1 = 0

x^{4} - 113 x^{2} + 3136 = 0

What are the solutions to the equation 4x^3-6x^2+2x=0 ?
The solutions to the equation 4x^3-6x^2+2x=0 are x=0,x= 1/2 ,x=1
Find the zeros of 4x^3-6x^2+2x=0
The zeros of 4x^3-6x^2+2x=0 are x=0,x= 1/2 ,x=1