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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2-6x+80=-4 ?
- The solutions to the equation 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i
Find the zeros of 3x^2-6x+80=-4
- The zeros of 3x^2-6x+80=-4 are x=1+3sqrt(3)i,x=1-3sqrt(3)i