What is (25xy^2z)*(130x^2y^2z^2) ?

The solution to (25xy^2z)*(130x^2y^2z^2) is 3250x^3y^4z^3

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simplify (25xy^2z)*(130x^2y^2z^2)

simplify

(25 x y^{2} z) \cdot (130 x^{2} y^{2} z^{2})

3250 x^{3} y^{4} z^{3}

Solution steps

(25 x y^{2} z) (130 x^{2} y^{2} z^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x x^{2} = x^{1 + 2}

= 25 y^{2} z \cdot 130 x^{1 + 2} y^{2} z^{2}

Add the numbers:

1 + 2 = 3

= 25 y^{2} z \cdot 130 x^{3} y^{2} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{2} y^{2} = y^{2 + 2}

= 25 z \cdot 130 x^{3} y^{2 + 2} z^{2}

Add the numbers:

2 + 2 = 4

= 25 z \cdot 130 x^{3} y^{4} z^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z z^{2} = z^{1 + 2}

= 25 \cdot 130 x^{3} y^{4} z^{1 + 2}

Add the numbers:

1 + 2 = 3

= 25 \cdot 130 x^{3} y^{4} z^{3}

Multiply the numbers:

25 \cdot 130 = 3250

= 3250 x^{3} y^{4} z^{3}

e^{- 3.742} \cdot (3.742)^{2} \frac{1}{2 !}

5 e^{- \frac{1}{2}}

(\frac{x ^{4}}{2} + \frac{x ^{4}}{12}) e^{- x}

0.85014 \cdot 6^{- 1}

1.85 \cdot (5.67 \cdot 1 0^{- 8}) \cdot (31 3^{4} - 30 6^{4})

What is (25xy^2z)*(130x^2y^2z^2) ?
The solution to (25xy^2z)*(130x^2y^2z^2) is 3250x^3y^4z^3