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Frequently Asked Questions (FAQ)
What are the solutions to the equation 108=-16x^2-22+220 ?
- The solutions to the equation 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))
Find the zeros of 108=-16x^2-22+220
- The zeros of 108=-16x^2-22+220 are x=(3sqrt(5))/(2sqrt(2)),x=-(3sqrt(5))/(2sqrt(2))