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Frequently Asked Questions (FAQ)
What are the solutions to the equation (0-4)^2+(y+2)^2=25 ?
- The solutions to the equation (0-4)^2+(y+2)^2=25 are y=1,y=-5
Find the zeros of (0-4)^2+(y+2)^2=25
- The zeros of (0-4)^2+(y+2)^2=25 are y=1,y=-5