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Frequently Asked Questions (FAQ)
What are the solutions to the equation (x+2)^2-4x+4=0 ?
- The solutions to the equation (x+2)^2-4x+4=0 are x=2sqrt(2)i,x=-2sqrt(2)i
Find the zeros of (x+2)^2-4x+4=0
- The zeros of (x+2)^2-4x+4=0 are x=2sqrt(2)i,x=-2sqrt(2)i