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Frequently Asked Questions (FAQ)
What are the solutions to the equation (1-4x)^2+5=(2-3x)(1-5x) ?
- The solutions to the equation (1-4x)^2+5=(2-3x)(1-5x) are x=-1,x=-4
Find the zeros of (1-4x)^2+5=(2-3x)(1-5x)
- The zeros of (1-4x)^2+5=(2-3x)(1-5x) are x=-1,x=-4