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Frequently Asked Questions (FAQ)
What are the solutions to the equation 3x^2+42x=-171 ?
- The solutions to the equation 3x^2+42x=-171 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i
Find the zeros of 3x^2+42x=-171
- The zeros of 3x^2+42x=-171 are x=-7+2sqrt(2)i,x=-7-2sqrt(2)i