What is the value of 1+0.2*((1.8)/(1.2))*tan(60) ?

The value of 1+0.2*((1.8)/(1.2))*tan(60) is 1+(3sqrt(3))/(10)

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1+0.2((1.8)/(1.2))tan(60)

1 + 0.2 \cdot (\frac{1.8}{1.2}) \cdot tan (6 0^{\circ})

1 + \frac{3 3}{10}

Decimal Notation

1.51961 \dots

Solution steps

1 + 0.2 (\frac{1.8}{1.2}) tan (6 0^{\circ})

= 1 + \frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} tan (6 0^{\circ})

Use the following trivial identity:

tan (6 0^{\circ}) = 3

tan (6 0^{\circ})

tan (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 3

= 1 + \frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} 3

Simplify

1 + \frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} 3 : 1 + \frac{3 3}{10}

1 + \frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} 3

\frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} 3 = \frac{3 3}{10}

\frac{1}{5} \cdot \frac{\frac{9}{5}}{\frac{6}{5}} 3

\frac{\frac{9}{5}}{\frac{6}{5}} = \frac{3}{2}

\frac{\frac{9}{5}}{\frac{6}{5}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{9 \cdot 5}{5 \cdot 6}

Cancel the common factor:

5

= \frac{9}{6}

Cancel the common factor:

3

= \frac{3}{2}

= 3 \frac{1}{5} \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 3 3}{5 \cdot 2}

Multiply the numbers:

1 \cdot 3 = 3

= \frac{3 3}{5 \cdot 2}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{3 3}{10}

= 1 + \frac{3 3}{10}

= 1 + \frac{3 3}{10}

3.55 cos (\frac{π}{6} \cdot 7) + 19.15

arccos (- \frac{6}{7})

70 sin (3 0^{\circ})

5 sin (31 5^{\circ})

cos (49.9 6^{\circ})

What is the value of 1+0.2*((1.8)/(1.2))*tan(60) ?
The value of 1+0.2*((1.8)/(1.2))*tan(60) is 1+(3sqrt(3))/(10)